Calling all gophers!
It’s time to talk about… Calls!
Calls
Given an expression
fwith a core typeFof function type,f(a1, a2, … an)calls
fwith argumentsa1, a2, … an.
This basic syntax is common to many languages, so should not feel at all strange if you have any programming experience at all.
So let’s dive right into the nitty-gritty details…
… Except for one special case, arguments must be single-valued expressions assignable to the parameter types of
Fand are evaluated before the function is called.
So we’ll talk about the special case later. For today, we’ll address the two other points made in this sentence.
- Arguments must be single-valued expressions. Let’s consider some examples and counter-examples. Assuming a function
fof typefunc(int, int, int):
f(1, 2, 3) // valid: Three single-valued expressions, 1, 2, and 3
f(1+2, 10-9, 3*4) // valid: Each expression evaluates to a single value
func one() int {
return 1
}
f(one(), one(), one()) // valid: one() evaluates to a single expression
func two() (int, int) {
return 2, 3
}
f(two(), one()) // invalid: two() evaluates to two expressions
// However, the likely intent of the above can be rewritten as:
a, b := two()
f(a, b, one())
- Arguments must be assignable to the parameter types of F. This one should be pretty obvious, especially if you’re familiar with strictly-typed languages.
f("one", float64(1.23), struct{ Name string}{Name: "Bob"}) // Invalid: f expects three ints
Quotes from The Go Programming Language Specification Version of August 2, 2023